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MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781305581159
Author: Nicholas J. Garber; Lester A. Hoel
Publisher: Cengage Learning US
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Question
Chapter 15, Problem 12P
To determine
(a)
The central angle of the curve for the highway design engineer to obtain simple curve to join tangents.
To determine
(b)
Radius of the curve.
To determine
(c)
Length of the tangent of the curve.
To determine
(d)
Station of the PC.
To determine
(e)
Length of the curve.
To determine
(f)
Station of the PT.
To determine
(g)
Deflection angle and chord from the PC to the first full station of the curve.
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The given beam has continuous lateral support. If the live load is twice the dead load, what is the
maximum total service load, in kips / ft, that can be supported? A992 steel is used: Fy = 50 ksi,
Fu=65 ksi. Take L = 30 ft.
bf
For W40 x 149:
2tf
=
7.11,
=
=
54.3, Z 598 in.³
tw
W
W40 X 149
L
(Express your answers to three significant figures.)
a. Use LRFD.
Wtotal =
kips/ft
b. Use ASD.
Wtotal
kips/ft
The beam shown in the figure below is a W16 × 31 of A992 steel and has continuous lateral support.
The two concentrated loads are service live loads. Neglect the weight of the beam and determine
whether the beam is adequate. Suppose that P = 52 k.
For W16 × 31: d = 15.9 in., tw
=
0.275 in., h/tw = 51.6,
and M = M₁ = 203 ft-kip, Mn/₁ = Mp/α = 135 ft-kip.
P
Р
W16 x 31
a. Use LRFD.
Calculate the required moment strength, the allowable shear strength, and the maximum shear.
(Express your answers to three significant figures.)
Mu
=
OvVn
=
ft-kip
kips
kips
Vu =
Beam is -Select-
b. Use ASD.
Calculate the required moment strength, the allowable shear strength, and the maximum shear.
(Express your answers to three significant figures.)
Ma =
Vn/b
-
Va =
Beam is -Select-
ft-kip
kips
kips
Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from the list below will
become slender.
bf/2tfh/tw
Shape
W12 × 72
8.99
22.6
W12 × 26
8.54
47.2
M4 × 6
11.9
22.0
M12 x 11.8
6.81
62.5
M6 × 4.4
5.39
47.0
S24 × 80
4.02
41.4
S10 × 35
5.03
13.4
(Express your answer to three significant figures.)
Fy
=
ksi
To which shape does this value apply?
-Select-
✓
Chapter 15 Solutions
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