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MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781305581159
Author: Nicholas J. Garber; Lester A. Hoel
Publisher: Cengage Learning US
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Question
Chapter 15, Problem 10P
To determine
(a)
The length of the vertical curve using the AASHTO method.
To determine
(b)
The station of the BVC of the crest vertical curve.
To determine
(c)
The elevation of the BVC of the crest vertical curve.
To determine
(d)
The station of the EVC of the crest vertical curve.
To determine
(e)
The elevation of the EVC of the crest vertical curve.
To determine
(f)
The station of the high point of the crest vertical curve.
To determine
(g)
The elevation of the high point of the crest vertical curve.
To determine
(h)
The elevation of station
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Students have asked these similar questions
A +2.5% grade intersects with a –1.5% grade at station (53+524.25) at an elevation of 90 m.
If the design speed is 90 km/h, use AASHTO (2011) criteria to determine:
The minimum length of vertical curve using the rate of vertical curvature.
The stations and elevations of the BVC and EVC.
The elevation of each 20-m station.
The station and elevation of the highpoint.
2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial
grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00
with its elevation of 1,005 ft. Please determine following.
a. PVC station
b. PVC elevation
C. PVT station
d. PVT elevation
e. The station where the highest elevation is located
f. The highest elevation on the road
g. The stations where the road elevation is 995 feet.
Crest Vertical Curve
PVI = 110+00
sta
Design Speed: 70 mph
Yev= 1,005'
PVI
Highest elevation
PVI
2.5%
-2.0%
PVC
PVT
Elevation
= 995 ft
L=1,115 ft
A parabolic curve has a descending grade of -0.8% and an ascending grade of
+0.4% that intersect at station 10 + 020 with an elevation of 240.600 m. If the
maximum allowable rate of change of grade for this curve is 0.15% per 20 m
stations, determine the following:
a. The maximum probable length of the parabolic curve
b. The location and elevation of the lowest point of the curve
c. The elevation at station 10 + 000
Chapter 15 Solutions
MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
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Similar questions
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- An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.arrow_forwardAn equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20arrow_forwardQ6. To help improve the safety of at-grade intersection of two roads, the intersection is being redesigned so that the E-W road will pass underneath the N-S road. Currently the vertical alignment of the E-W road consists of a crest vertical curve joining a 4% upgrade to a 3% downgrade. The existing vertical curve is 138 m long, the PVC of this curve is at station 14+47, and the elevation of the PVC is 477 m. The centerline of the N-S road is at station 15+45. Your job is to find the shortest vertical curve that provides 6.0 m of clearance between the new E-W road and the N-S road.arrow_forward
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