(a)
Interpretation: The molarity of 0.50 mole of KBr in 250 mL solution should be calculated.
Concept Introduction:
Molarity is the number of mol of solute dissolved per liter of the given solution.
The formula to calculate molarity of solution is,
Here, M is molarity, n is number of moles and V is volume of solution in L.
(b)
Interpretation: The molarity 0.50 mole of KBr in 500 mL solution should be calculated.
Concept Introduction:
Molarity is the number of mol of solute dissolved per liter of the given solution.
The formula to calculate molarity of solution is,
Here, M is molarity, n is number of moles and V is volume of solution in L.
(c)
Interpretation: The molarity of 0.50 mole of KBr in 750 mL solution should be calculated.
Concept Introduction:
Molarity is the number of mol of solute dissolved per liter of the given solution.
The formula to calculate molarity of solution is,
Here, M is molarity, n is number of moles and V is volume of solution in L.
(d)
Interpretation: The molarity of 0.50 mole of KBr in 1.0 L solution should be calculated.
Concept Introduction:
Molarity is the number of mol of solute dissolved per liter of the given solution.
The formula to calculate molarity of solution is,
Here, M is molarity, n is number of moles and V is volume of solution in L.
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Chapter 15 Solutions
EBK INTRODUCTORY CHEMISTRY
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- Determine the molarity for each of the following solutions: (a) 0.444 mol of CoCl2 in 0.654 L of solution (b) 98.0 g of phosphoric acid, H3PO4, in 1.00 L of solution (c) 0.2074 g of calcium hydroxide, Ca(OH)2, in 40.00 mL of solution (d) 10.5 kg of Na2SO410H2O in 18.60 L of solution (e) 7.0103 mol of I2 in 100.0 mL of solution (f) 1.8104 mg of HCI in 0.075 L of solutionarrow_forwardA student was given a 1.6240-g sample of a mixture of sodium nitrate and sodium chloride and was asked to find the percentage of each compound in the mixture. She dissolved the sample and added a solution that contained an excess of silver nitrate. The silver ion precipitated all of the chloride ion in the mixture as silver chloride. It was filtered, dried, and weighed. Its mass was 2.056g. What was the percentage of each compound in the mixture?arrow_forwardCalcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion are usually prepared by dissolving calcium carbonate in acid. What mass of CaCO3 should be taken to prepare 500. mL of 0.0200 M calcium ion solution?arrow_forward
- You wish to prepare 1 L of a 0.02-M potassium iodate solution. You require that the final concentration be within 1% of 0.02 M and that the concentration must be known accurately to the fourth decimal place. How would you prepare this solution? Specify the glassware you would use, the accuracy needed for the balance, and the ranges of acceptable masses of KIO3 that can be used.arrow_forwardA common method for determining how much chloride ion is present in a sample is to precipitate the chloride from an aqueous solution of the sample with silver nitrate solution and then to weigh the silver chloride that results. The balanced net ionic reaction is :math>Ag+(aq)+Cl(aq)AgCl(s) ppose a 5.45-g sample of pure sodium chloride is dissolved in water and is then treated with a solution containing 1.15 g of silver nitrate. Will this quantity of silver nitrate be capable of precipitating all the chloride ion from the sodium chloride sample?arrow_forwardMolarity is a conversion factor relating moles of solute in solution to the volume of the solution. How does one use molarity as a conversion factor to convert from moles of solute to volume of solution, and from volume of solution to moles of solute present?arrow_forward
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