Chapter 15, Problem 10TYPSS

Summary Introduction

To review:

Considering each replication fork moves at a rate of 500 base pairs per second, calculate the time required to replicate the Escherichia coli of 4.6 million base pairs (bp) from a single origin of replication.

Introduction:

The replication of the E. coli chromosome is bidirectional. Thus, half of the time is required for replicating the base pairs.

$\text{Number of base}\text{pair replicated}=\text{4}\text{.6 million bp}$

$\text{Number of bp replicated in one second}=\text{500 bp}$