Explanation Express an energy balance on the control volume to determine the specific humidity of the air. h 1 + ( ω 2 − ω 1 ) h w = h 2 (I) Here, initial specific enthalpy is h 1 , final specific enthalpy is h 2 , specific enthalpy of water is h w , and initial and final specific humidity of air is ω 1 and ω 2 respectively. Express saturation pressure of water at temperature of 30°C . ϕ 1 = ω 1 P 1 ( 0.622 + ω 1 ) P g 1 = ω 1 P 1 ( 0.622 + ω 1 ) P sat@35°C (II) Here, initial pressure is P 1 and saturation pressure at temperature of 35°C is P sat@35 ° C . Conclusion: From Figure A-31, “Psychrometric chart”, write the value of final specific enthalpy and final specific humidity of air corresponding to total pressure of 98 kPa and dry bulb temperature of 35°C . h 2 = 78.11 kJ / kg dry air ω 2 = 0.02079 kg H 2 O / kg dry air Refer Table A-4, “saturated water-temperature table”, and write the specific enthalpy of water at temperature of 25°C . h w = h f = 104.83 kJ / kg Here, specific enthalpy at saturated liquid is h f . Substitute 78.11 kJ / kg dry air for h 2 , 0.02079 kg H 2 O / kg dry air for ω 2 and 104

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Chapter 14 Solutions

THERMODYNAMICS-SI ED. EBOOK >I<

Ch. 14.7 - What is the difference between dry air and...Ch. 14.7 - What is vapor pressure?Ch. 14.7 - What is the difference between the specific...Ch. 14.7 - Can the water vapor in air be treated as an ideal...Ch. 14.7 - Explain how vapor pressure of the ambient air is...Ch. 14.7 - Is the relative humidity of saturated air...Ch. 14.7 - Moist air is passed through a cooling section...Ch. 14.7 - How will (a) the specific humidity and (b) the...Ch. 14.7 - Prob. 9P Ch. 14.7 - Consider a tank that contains moist air at 3 atm...

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