Explanation Given : To avoid skidding frictional force F = m a , a is the acceleration vector , max magnitude of frictional force is μ m g Formula Used : The acceleration vector is given by: a ( t ) = v ' ( t ) T + k v 2 ( t ) N (1) a is the acceleration vector v is velocity vector T is tangential vector N is normal unit vector k is curvature Calculation : It is given to avoid skidding frictional force is applied as: F = m a (2) Using equation (1) to compute magnitude of acceleration vector: | | a | | 2 = ( v ' T + k v 2 N ) 2 = ( v ' ) 2 T . T + 2 k v 2 v ' N . T + k 2 v 4 N . N N and T are orthogonal, therefore T . T = N . N = 1 a n d T ...

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 14.5, Problem 57E

To determine

Show that ${(v^{'})}^{2} + {(\frac{v^{2}}{R})}^{2} \leq {(μ g)}^{2}$

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Chapter 14.5, Problem 56E

Chapter 14.5, Problem 58E

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Chapter 14 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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