Explanation Given info: Given point p = ( 3 , − 5 , 7 ) V → = ( 3 , 0 , 1 ) Concept used: ( r → − r 0 → ) = t v → V → Is vector parallel to given line r → Is position vector of variable point? r 0 → Is position vector of given point Calculation: Let co-ordinate of variable point is ( x , y , z ) on the line. So position vector of variable point on the line = x i ∧ + y j ∧ + z k ∧ Given point ( 3 , − 5 , 7 ) Position vector of given point = 3 i ∧ − 5 j ∧ + 7 k ∧ Equation of line in vector format is given by ( x i ∧ + y j ∧ + z k ∧ ) − ( 3 i ∧ − 5 j ∧ + 7 k ∧ ) = t ( 3 i ∧ + 0 j ∧ + 7 k ∧ ) V → = ( 3 , ...

4th Edition

ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 14.1, Problem 5E

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Find a vector parameterization of the line through $p = (3, - 5, 7)$ in the direction $\vec{V} = (3, 0, 1)$

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Chapter 14.1, Problem 4E

Chapter 14.1, Problem 6E

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Chapter 14 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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Find a vector parameterization of the line through p = ( 3 , − 5 , 7 ) in the direction V → = ( 3 , 0 , 1 )

Solution Summary: The author explains how to determine a vector parameterization of the line through p = ( 3, 5, 7 ) in the direction V

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Find a vector parameterization of the line through $p = (3, - 5, 7)$ in the direction $\vec{V} = (3, 0, 1)$

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Chapter 14 Solutions

Find a vector parameterization of the line through p = ( 3 , − 5 , 7 ) in the direction V → = ( 3 , 0 , 1 )

Solution Summary: The author explains how to determine a vector parameterization of the line through p = ( 3, 5, 7 ) in the direction V

Concept explainers

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Find a vector parameterization of the line through p=(3,−5,7) in the direction V→=(3,0,1)

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Chapter 14 Solutions

Find a vector parameterization of the line through $p = (3, - 5, 7)$ in the direction $\vec{V} = (3, 0, 1)$