Express the area of the given surface as an iterated double integral in polar coordinates, and then find the surface area. The portion of the surface z = x y that is above the sector in the first quadrant bounded by the lines y = x / 3 , y = 0 , and the circle x 2 + y 2 = 9.
Express the area of the given surface as an iterated double integral in polar coordinates, and then find the surface area. The portion of the surface z = x y that is above the sector in the first quadrant bounded by the lines y = x / 3 , y = 0 , and the circle x 2 + y 2 = 9.
Express the area of the given surface as an iterated double integral in polar coordinates, and then find the surface area.
The portion of the surface
z
=
x
y
that is above the sector in the first quadrant bounded by the lines
y
=
x
/
3
,
y
=
0
,
and the circle
x
2
+
y
2
=
9.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Inverse laplace transform
Lect: Huda I
H.w
1- F(S)=
A- Find - F(s) of the following
S
(s+1)5
1
2- F(s)
s² (s-a)
5+5
3- F(s)=
s2+4s+3
1
4- F(s)=
(s+2)2(s-2)
3s2-7s+5
5- F(s)=
(s-1)(s2-5s+6)
Inverse laplace transform
Lect :Huda I
H.w
A- Find L-1 F(s) of the following
1- F(S)=
2- F(s)-
S
(+1)5
s² (s-a)
5+5
s2+4s+3
3- F(s)-
1
4- F(s)-
(s+2)2(s-2)
3s2-7s+5
5- F(s)-
(s-1)(s2-55+6)
B-Solve the D.E of the following:
1- y'+3y+2fy dt = f(t) for y(0)-1 if f(t) is the function
whose graph is shown below
2
1 2
2-y+4y-u(t)
for y(0)=y'(0)=0
3- y"+4y'+13y= e−2t sin3t
for y(0)-1 and y'(0)=-2
17
Probability And Statistical Inference (10th Edition)
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