Explanation Given: f ( x ) = 2 x 2 + 3 x c = 1 Formula used: The derivative of y = f ( x ) at c is given by: f ′ ( c ) = lim x → c f ( x ) − f ( c ) x − c Calculation: Here, f ( x ) = 2 x 2 + 3 x and c = 1 . f ( c ) = f ( 1 ) = 2 ( 1 ) 2 + 3 ( 1 ) = 2 + 3 = 5 Therefore, f ′ ( 1 ) = lim x → 1 f ( x )

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Chapter 14.4, Problem 25AYU

To determine

To find: The derivative of $f (x) = 2 x^{2} + 3 x$ at 1.

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Chapter 14.4, Problem 24AYU

Chapter 14.4, Problem 26AYU

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