Explanation Given: f ( x ) = x 2 − 2 x + 3 Point: ( −1 , 6 ) Formula used: The slope of the tangent to the curve y = f ( x ) is the derivative of f ( x ) w.r.to x ie d y d x . Calculation: Here, y = f ( x ) = x 2 − 2 x + 3 Slope of the tangent is given by; d y d x = d d x ( x 2 − 2 x + 3 ) d y d x = d d x ( x 2 )

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Chapter 14.4, Problem 17AYU

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To find: The slope of the tangent to the function $y = f (x)$ at the indicated point.

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Chapter 14.4, Problem 16AYU

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Chapter 14 Solutions

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The slope of the tangent to the function y = f ( x ) at the indicated point.

Solution Summary: The author calculates the slope of the tangent to the function y = f ( x ) at the indicated point.

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To find: The slope of the tangent to the function $y = f (x)$ at the indicated point.

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Chapter 14 Solutions

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The slope of the tangent to the function y = f ( x ) at the indicated point.

Solution Summary: The author calculates the slope of the tangent to the function y = f ( x ) at the indicated point.

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To find: The slope of the tangent to the function y = f( x ) at the indicated point.

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Chapter 14 Solutions

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To find: The slope of the tangent to the function $y = f (x)$ at the indicated point.