Explanation Definition used: General quadratic equation : “Given that a , b , and c are constant ( a ≠ 0 ) , the equation a x 2 + b x 2 + c = 0 is called the general quadratic equation in x ”. Calculation: Consider the equation 10 x − 2 + 3 x − 1 − 1 = 0 . In order to find the value of x , first rewrite the equation in quadratic form. Substitute y = x − 1 in 10 x − 2 + 3 x − 1 − 1 = 0 and simplify the equation as follows. 10 y 2 + 3 y − 1 = 0 10 y 2 + 5 y − 2 y − 1 = 0 5 y ( 2 y + 1 ) − 1 ( 2 y + 1 ) = 0 ( 5 y − 1 ) ( 2 y + 1 ) = 0 On further simplification, 5 y − 1 = 0 or 2 y + 1 = 0 5 y = 1 or 2 y = − 1 x − 1 = 1 5 or x − 1 = − 1 2 [ ∵ y = x − 1 ] x = 5 or x = − 2 Thus, the solutions of the equation are x = 5 , and x = − 2 _

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 14.3, Problem 6E

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To solve: The equation 10x−2+3x−1−1=0 algebraically.

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Chapter 14.3, Problem 5E

Chapter 14.3, Problem 7E

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Chapter 14 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 14.1 - In Example 7, determine how many times the rocket...Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E

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The equation 10 x − 2 + 3 x − 1 − 1 = 0 algebraically.

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To solve: The equation 10x−2+3x−1−1=0 algebraically.

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Chapter 14 Solutions