Explanation It is given that the total resistance of the set of equal resistor is 78.0 Ω and the set of two fewer equal resistor ha resistance 78.0 Ω . Let consider n be the number of resistors in the first set with each resistance R then, n R = 78 R = 78 n It is also given that each resistor in the series is 1.3 Ω greater than the each of the first set that is ( R + 1.3 ) . ( n − 2 ) ( R + 1.3 ) = 78 ( n − 2 ) ( 78 n + 1.3 ) = 78 78 n n + 1.3 n − 2 78 n − 2 ⋅ 1.3 = 78 1.3 n + 75.4 − 156 n = 78 1

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 14.2, Problem 39E

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The number of resistor in each of the set of the electrical resistors.

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Chapter 14.2, Problem 38E

Chapter 14.2, Problem 40E

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Chapter 14 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 14.1 - In Example 7, determine how many times the rocket...Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E

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