Explanation Definition used: General quadratic equation : “Given that a , b , and c are constant ( a ≠ 0 ) , the equation a x 2 + b x + c = 0 is called the general quadratic equation in x ”. Calculation: Consider the equation μ = A + B λ − 2 + C λ − 4 . In order to find the value of λ , first rewrite the equation in quadratic form. Substitute y = λ − 2 in μ = A + B λ − 2 + C λ − 4 and simplify the equation as follows. μ = A + B y + C y 2 C y 2 + B y + ( A − μ ) = 0 y = − B ± B 2 − 4 C ( A − μ ) 2 C y = − B ± B 2 − 4 A C + 4 μ C 2 C On further simplification, λ − 2 = − B ± B 2 − 4 A C + 4 μ C 2 C λ = 2 C − B ± B 2 − 4 A C + 4 μ C Thus, the solutions of the equation is λ = 2 C − B ± B 2 − 4 A C + 4 μ C _ . Check the answer as follows. Substitute λ = 2 C − B ± B 2 − 4 A C + 4 μ C in μ = A + B λ − 2 + C λ − 4

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 14.3, Problem 38E

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To solve: The equation μ=A+Bλ−2+Cλ−4 algebraically.

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Chapter 14.3, Problem 37E

Chapter 14.3, Problem 39E

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Chapter 14 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 14.1 - In Example 7, determine how many times the rocket...Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E

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The equation μ = A + B λ − 2 + C λ − 4 algebraically.

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To solve: The equation μ=A+Bλ−2+Cλ−4 algebraically.

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Chapter 14 Solutions