To determine To find: The value of C x y ( x , y ) where C ( x , y ) = 3 x 2 + 10 x y − 8 y 2 + 4 x − 15 y − 120 . Explanation Obtain the second order partial derivatives C x y ( x , y ) . The function is C ( x , y ) = 3 x 2 + 10 x y − 8 y 2 + 4 x − 15 y − 120 . Find the partial derivative with respect to x . That is, treating y as a constant differentiate with respect to x . C x ( x , y ) = ∂ ∂ x ( 3 x 2 + 10 x y − 8 y 2 + 4 x − 15 y − 120 ) = ∂ ∂ x ( 3 x 2 ) + ∂ ∂ x ( 10 x y ) − ∂ ∂ x ( 8 y 2 ) + ∂ ∂ x ( 4 x ) − ∂ ∂ x ( 15 y ) − ∂ ∂ x ( 120 ) = ( 3 ) ∂ ∂ x ( x 2 ) + ( 10 y ) ∂ ∂ x ( x ) − ∂ ∂ x ( 8 y 2 ) + ( 4 ) ∂ ∂ x ( x ) − ∂ ∂ x ( 15 y ) − ∂ ∂ x ( 120 ) Simplify further and obtain the partial derivative

College Mathematics for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

14th Edition

ISBN: 9780134674148

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen, Christopher J. Stocker

Publisher: PEARSON

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Chapter 14.2, Problem 57E

To determine

To find: The value of Cxy(x,y) where C(x,y)=3x2+10xy−8y2+4x−15y−120.

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Chapter 14.2, Problem 56E

Chapter 14.2, Problem 58E

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Chapter 14 Solutions

College Mathematics for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

Ch. 14.1 - Matched Problem 1 Find C(20, 10) for the cost...Ch. 14.1 - Prob. 2MP Ch. 14.1 - Prob. 3MP Ch. 14.1 - Prob. 4MP Ch. 14.1 - Prob. 5MP Ch. 14.1 - Prob. 6MP Ch. 14.1 - Prob. 7MP Ch. 14.1 - Prob. 1ED Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E

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