Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Solution Summary: The author evaluates the value of the line integral displaystyleundersetCint.
Scalar line integrals with arc length as parameterEvaluate the following line integrals.
13.
∫
C
(
x
2
−
2
y
2
)
d
s
;
C is the line circle
r
(
s
)
=
(
s
/
2
,
s
/
2
)
, for
0
≤
s
≤
4
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
For each given function f(x) find f'(x) using the rules learned in section 9.5.
1. f(x)=x32
32x
2. f(x)=7x+13
3. f(x) =
x4
4. f(x) = √√x³
5. f(x) = 3x²+
3
x2
Find:
lim x →-6 f (x)
limx-4 f (x)
lim x-1 f (x)
lim x →4 f (x)
(-6,3) •
(-1,5)
-8
-7
(-6,-2)
4+
(4,5)
(4,2) •
(-1,1)
-6
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