Explanation Given Information: The provided function is y = 6 sin ( 2 x − 180 ° ) . Formula Used: If an equation written in the form of y = A sin ( a x + b ) then, the amplitude of the function is represented by A , period represented by P = 360 ° a and phase shift is represented by b a Calculation: Consider the provided function: y = 6 sin ( 2 x − 180 ° ) Now, compare the provided function y = 6 sin ( 2 x − 180 ° ) with the function y = A sin ( a x + b ) . So, it can be concluded that, Amplitude = 6 Phase shift b a = − 180 ° 2 = − 90 ° And, Period P = 360 2 = 180 ° Thus, the amplitude is 6 and period is 180 ° in the given function y = 6 sin ( 2 x − 180 ° ) . Graph: Consider the provided function: y = 6 sin ( 2 x − 180 ° ) Now, obtain the values of y by assuming corresponding values of x as: Substitute x = 0 in the function y = 6 sin ( 2 x − 180 ° ) . y = 6 sin ( 2.0 − 180 ° ) = 6 sin ( − 180 ° ) = 0 Substitute x = 15 in the function y = 6 sin ( 2 x − 180 ° ) . y = 6 sin ( 2.15 − 180 ) = 6 sin ( 30 − 180 ) = 6 sin ( − 150 ) = − 3 Substitute x = 30 in the function y = 6 sin ( 2 x − 180 ° ) . y = 6 sin ( 2.30 − 180 ) = 6 sin ( 60 − 180 ) = 6 sin ( − 120 ) = − 5

12th Edition

ISBN: 9781337630580

Author: Dale Ewen

Publisher: Cengage Learning

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Chapter 14, Problem 9R

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To calculate: The period and amplitude of the given expression y=6sin(2x−180°) and graph the provided function.

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Chapter 14, Problem 8R

Chapter 14, Problem 10R

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The period and amplitude of the given expression y = 6 sin ( 2 x − 180 ° ) and graph the provided function.

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To calculate: The period and amplitude of the given expression y=6sin(2x−180°) and graph the provided function.

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Chapter 14 Solutions