Chapter 14, Problem 82E

Interpretation Introduction

Interpretation:

For each of the given solution, the $\text{pOH}$ value is to be determined with the help of hydronium ion concentration, i.e., $\left[{\text{H}}_{\text{3}}{\text{O}}^{+}\right]$.

Concept introduction:

The $\text{pH}$ of the solution is given by the negative of the logarithm of $\left[{\text{H}}_{\text{3}}{\text{O}}^{+}\right]$.

Mathematically, it is written as

$\text{pH}=-\log \left[{\text{H}}_{\text{3}}{\text{O}}^{+}\right]$ Similarly, the $\text{pOH}$ value of the solution is the negative of the logarithm of $\left[{\text{OH}}^{-}\right]$.

Mathematically, it is written as

$\text{pOH}=-\log \left[{\text{OH}}^{-}\right]$

The sum of $\text{pH}$ and $\text{pOH}$ in a solution is always equals to a constant at a constant temperature. At ${25}^{°}\text{C}$, the sum of $\text{pH}$ and $\text{pOH}$ can be expressed as

$\text{pH}+\text{pOH}=\text{14}\text{.00}$