Concept explainers
a) CHCl3, chloroform
Interpretation:
The line – bond structure, showing all nonbonding electrons for CHCl3, chloroform is to be given.
Concept introduction:
A covalent bond is formed by mutual sharing of two electrons between the atoms, each atom giving one electron for sharing. Such a covalent bond, that is, a pair of shared electrons is represented as a line between the atoms, for example as A-B. Valence electrons that are not used for bonding are called lone-pair of electrons or nonbonding electrons. The nonbonding electrons are usually omitted while drawing line-bond structure.
To determine:
The line – bond structure, showing all nonbonding electrons for CHCl3, chloroform
b) CH3NH2, methylamine
Interpretation:
The line – bond structure, showing all nonbonding electrons for CH3NH2, methylamine is to be given.
Concept introduction:
A covalent bond is formed by mutual sharing of two electrons between the atoms, each atom giving one electron for sharing. Such a covalent bond, that is, a pair of shared electrons is represented as a line between the atoms, for example as A-B. Valence electrons that are not used for bonding are called lone-pair of electrons or nonbonding electrons. The nonbonding electrons are usually omitted while drawing line-bond structure.
To determine:
The line – bond structure, showing all nonbonding electrons for CH3NH2, methylamine.
c) H2S, hydrogen sulfide
Interpretation:
The line – bond structure, showing all nonbonding electrons for H2S, hydrogen sulfide is to be given.
Concept introduction:
A covalent bond is formed by mutual sharing of two electrons between the atoms, each atom giving one electron for sharing. Such a covalent bond, that is, a pair of shared electrons is represented as a line between the atoms, for example as A-B. Valence electrons that are not used for bonding are called lone-pair of electrons or nonbonding electrons. The nonbonding electrons are usually omitted while drawing line-bond structure.
To determine:
The line – bond structure, showing all nonbonding electrons for H2S, hydrogen sulfide.
d) CH3 Li, methyllithium
Interpretation:
The line – bond structure, showing all nonbonding electrons for CH3 Li, methyllithium is to be given.
Concept introduction:
A covalent bond is formed by mutual sharing of two electrons between the atoms, each atom giving one electron for sharing. Such a covalent bond, that is, a pair of shared electrons is represented as a line between the atoms, for example as A-B. Valence electrons that are not used for bonding are called lone-pair of electrons or nonbonding electrons. The nonbonding electrons are usually omitted while drawing line-bond structure.
To determine:
The line – bond structure, showing all nonbonding electrons for CH3 Li, methyllithium
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Chapter 1 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
- (6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forwardNonearrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception to the general ionization energy (IE) trend. For the two elements involved, answer the following questions. Be sure to cite sources for all physical data that you use. a. (2 pts) Identify the two elements and write their electronic configurations. b. (2 pts) Based on their configurations, propose a reason for the IE trend exception. c. (5 pts) Calculate effective nuclear charges for the last electron in each element and the Allred-Rochow electronegativity values for the two elements. Can any of these values explain the IE trend exception? Explain how (not) - include a description of how IE relates to electronegativity.arrow_forward
- Please explain thoroughly and provide steps to draw.arrow_forwardAs you can see in the picture, the instrument uses a Xe source. Given that the instrument is capable of measuring from 200-800nm, if Xe was not used, what other source(s) could be used? Refer to figure 7-3. How many monochrometers does this instrument have? Why? Trace the light as it goes from the Xenon lamp all the way to the circle just slightly to the right and a little bit down from S4. What do you think that circle is? In class we talked about many types of these, which kind do you think this one is for a fluorimeter? Why? Explain. What is/are some strategy(ies) that this instrument has for dealing with noise that you see present in the optics diagram? Why does a fluorescence cuvette have to be clear on four sides?arrow_forwardProvide steps and thoroughly solve.arrow_forward
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning