(a) Explanation Given The balanced chemical reaction is, 2NO 2 ( g ) → 2 NO ( g ) + O 2 ( g ) The reaction follows the following data: S.No. Time(s) [ NO 2 ] ( M ) 1. 0.0 0.100 2. 5.0 0.017 3. 10.0 0.0090 4. 15.0 0.0062 5. 20.0 0.0047 The integrated rate equation of first order reaction is, ln [ NO 2 ] t = − k t + ln [ NO 2 ] 0 Where, [ NO 2 ] t is the concentration of the NO 2 at time t. [ NO 2 ] 0 is the initial concentration of NO 2 . k is the rate constant for the reaction. t is the time. Therefore, the plot of ln [ NO 2 ] t versus t gives a straight-line graph in first order reaction. The plot of ln [ NO 2 ] t versus t is drawn by considering the following data: ln[NO 2 ] S.No. Time(s) ln [ NO 2 ] t 1. 0.0 − 2.3025 2. 5.0 − 4 (b) Interpretation Introduction To determine: The rate constant of the given reaction. (c) Interpretation Introduction To determine: The rate of the given reaction at the given concentration.

14th Edition

ISBN: 9780136873891

Author: Brown

Publisher: PEARSON

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Chapter 14, Problem 49E

(a)

Interpretation Introduction

To determine: The order of the given reaction by using appropriate graphs.

(b)

Interpretation Introduction

To determine: The rate constant of the given reaction.

(c)

Interpretation Introduction

To determine: The rate of the given reaction at the given concentration.

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Chapter 14, Problem 48E

Chapter 14, Problem 50E

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Chapter 14 Solutions

CHEMISTRY THE CENTRAL SCIENCE >EBOOK<

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

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