(a) Explanation Given The balanced chemical reaction is, SO 2 Cl 2 ( g ) → SO 2 ( g ) + Cl 2 ( g ) The reaction is first order with respect to SO 2 Cl 2 . The first order rate constant of the reaction at 660 K is 4.5 × 10 − 2 s − 1 . The initial partial pressure of SO 2 Cl 2 is 450 torr . The time taken by the reaction is 60 s . The partial pressure of SO 2 Cl 2 in the reaction is calculated by the formula, ln [ P ] t = − k t + ln [ P ] 0 Where, [ P ] t is the partial pressure of the SO 2 Cl 2 at time t (b) Interpretation Introduction To determine: The time at which the partial pressure of SO 2 Cl 2 in the reaction becomes one-tenth of its initial value.

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Chapter 14, Problem 43E

(a)

Interpretation Introduction

To determine: The partial pressure of SO2Cl2 in the given reaction after 60 s .

(b)

Interpretation Introduction

To determine: The time at which the partial pressure of SO2Cl2 in the reaction becomes one-tenth of its initial value.

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Chapter 14, Problem 42E

Chapter 14, Problem 44E

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Chapter 14 Solutions

CHM 101 VOL 1 2014 >IC<

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

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The partial pressure of SO 2 Cl 2 in the given reaction after 60 s .

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To determine: The partial pressure of SO2Cl2 in the given reaction after 60 s .

To determine: The time at which the partial pressure of SO2Cl2 in the reaction becomes one-tenth of its initial value.

Want to see the full answer?

Chapter 14 Solutions