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- The 13C NMR spectrum of 1-bromo-3-chloropropane contains peaks at δ 30, δ 35, and δ 43. Assign these signals to the appropriate carbons.arrow_forwardThe 13C-NMR spectrum of 3-methyl-2-butanol shows signals at 17.88 (CH3), 18.16 (CH3), 20.01 (CH3), 35.04 (carbon-3), and 72.75 (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.arrow_forwardWhich of the protons in the following molecule appear at the highest 8-value in the ¹H NMR spectrum? Explain your reasoning. H₂ iii iv H CH3 i y HCarrow_forward
- Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Provide structure for compound 2, explain how you reached your conclusion.arrow_forwardCompound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compound 1, explaining how you reach your conclusion.arrow_forwardBelow are the ¹H NMR spectrum of triphenylmethanol, benzophenone, and bromobenzene. Identify the compound corresponding to each ¹H NMR spectrum and draw the structure next to the ¹H NMR spectrum. Assign ALL peaks in each of the three ¹H NMR spectra. Hint: Conjugated systems (benzophenone) including an electronegative atom will cause a more downfield shift of ring protons in ¹H NMR compared with non-conjugated systems (bromobenzene). 8 8 8 7 7 7 6 6 6 5 5 5 4 PPM 4 PPM 4 PPM 3 3 3 2 2 2 1 1 1 0 0 0arrow_forward
- The 1H-NMR spectrum of ethanol shows a triplet at 1.23 ppm, a singlet at 2.61 pm, and a quartet at 3.69 ppm. Assign each signal to the protons it corresponds to in the molecule. Explain the splitting pattern observed for each signal.arrow_forwardDraw the H1 NMR spectra of ethylcyclopropane. Draw the chemical structure and predict the proton splitting and chemical shifts.arrow_forward1. How many proton signals would you expect to see in the ¹H-NMR spectrum of the following molecule? For each of the proton signals, predict the splitting pattern, assuming that you can see only 3-bond splitting.arrow_forward
- The 1H and 13C NMR for a compound with the formula C5H12O are shown. Determine the structure of this compound. Assign the peaks: assign “a” to the most shielded hydrogen(s) in your structure, “b” to next-most shielded, etc; use capital letters for carbons).arrow_forwardThe 1H-NMR spectrum of 1,3-propanediol (HO-CH2-CH2-CH2-OH) shows a quintet at 1.81 ppm, a singlet at 2.75 pm, and a triplet at 3.83 ppm. Assign each signal to the protons it corresponds to in the molecule. Explain the splitting pattern observed for each signal.arrow_forwardFollowing is the 1H-NMR spectrum of compound O, molecular formula C7H12. Compound O reacts with bromine in carbon tetrachloride to give a compound with the molecular formula C7H12Br2. The 13C-NMR spectrum of compound O shows signals at d 150.12, 106.43, 35.44, 28.36, and 26.36. Deduce the structural formula of compound O.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning