Chapter 14, Problem 36E

Interpretation Introduction

Interpretation:

The 0.1487 M sucrose solution with density 1.018 g/mL is mixed with 10% sucrose solution with density 1.038%. The mole percent of ${\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}$ in the mixed solution needs to be determined.

Concept introduction:

The mole percent of any substance can be calculated from the following relation:

$\%{\text{mole}}_{\text{A}}=\frac{{\text{mole}}_{\text{A}}}{{\text{mole}}_{\text{Solution}}}\times 100\%$

Here, ${\text{mole}}_{\text{A}}$ is number of moles of substance A wholes mole percent is required and ${\text{mole}}_{\text{Solution}}$ is number of moles of solution.