Chapter 14, Problem 110IAE

Interpretation Introduction

(a)

Interpretation:

Density of the solution should be calculated.

Concept introduction:

Compound with the high amount take as the solvent and the compound with the less amount take as the solute.

$\text{Density = }\frac{\text{Mass of solution }}{\text{Volume of solution}}$

Interpretation Introduction

(b)

Interpretation:

The percent of sucrose in the solution should be calculated.

Concept introduction:

$\text{Percent of compound A by mass = }\left(\frac{\text{Mass of compound A}}{(\text{Mass of compound A + Mass of compound B)}}\right)\times 100$

Interpretation Introduction

(c)

Interpretation:

The mole fraction of sucrose in the solution should be calculated.

Concept introduction:

$\begin{array}{l}\text{Number of moles = }\left(\frac{\text{mass of the compound}}{\text{molecular mass of the compound}}\right)\\ \text{Mole fraction of compound A = }\left(\frac{\text{Moles of compounn A}}{\text{Moles of cmpound A + Moles of compound B}}\right)\end{array}$

Interpretation Introduction

(d)

Interpretation:

Molality of the solution should be calculated.

Concept introduction:

$\begin{array}{l}\text{Molality of the solution = }\frac{\text{Amount of solute (moles)}}{\text{Mass of solvent (kilograms)}}\\ \end{array}$

Interpretation Introduction

(e)

Interpretation:

Molarity of the solution should be calculated.

Concept introduction:

$\begin{array}{l}\text{Molarity of the solution = }\frac{\text{Amount of solute (moles)}}{\text{Volume of the solution (Liters)}}\\ \end{array}$