Explanation Given: The different biology courses: Anatomy and Physiology (A), Introduction to Biology (B), and Biochemistry (C). The sections will be apportioned based on preregistration as shown in the table below. Course A B C Total Number of Students 311 219 160 690 Formula used: Jefferson’s Apportionment method: 1. Determine a modified divisor d , such that each group’s modified quota is rounded down. 2. Apportion to each group its modified lower quota. Calculation: Let us consider the modified divisor d = 28 . Use the formula of the modified quota, Modified quota of course A = 311 28 = 11.211 The modified quota of the course A is 11.211, and the modified lower quota to the nearest integer is 11. Thus, the Jefferson’s apportionment of the course A is 11. Obtain the modified quota of course B. Modified quota of course B = 219 28 = 7

A Survey of Mathematics with Applications (10th Edition) - Standalone book

10th Edition

ISBN: 9780134112107

Author: Allen R. Angel, Christine D. Abbott, Dennis Runde

Publisher: PEARSON

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Chapter 14, Problem 34RE

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The apportionment of each course using the Jefferson’s method.

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Chapter 14, Problem 33RE

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A Survey of Mathematics with Applications (10th Edition) - Standalone book

Ch. 14.1 - In Exercise 1-8, fill in the blank with an...Ch. 14.1 - In Exercise 1-8, fill in the blank with an...Ch. 14.1 - In Exercise 1-8, fill in the blank with an...Ch. 14.1 - In Exercise 1-8, fill in the blank with an...Ch. 14.1 - Prob. 5E Ch. 14.1 - In Exercise 1-8, fill in the blank with an...Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Plurality Three candidates are running for mayor...Ch. 14.1 - Prob. 10E

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The apportionment of each course using the Jefferson’s method.

Solution Summary: The author explains the Jefferson's apportionment of each course using the modified divisor d.

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The apportionment of each course using the Jefferson’s method.

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Chapter 14 Solutions