EBK ENGINEERING FUNDAMENTALS: AN INTROD
5th Edition
ISBN: 9780100543409
Author: MOAVENI
Publisher: YUZU
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Chapter 14, Problem 27P
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A- Design grit removal chamber for a W.W.P with hourly flow equal 5000
m'h
410 mark
05
An average operating data for conventional activated sludge treatment
plant is as follows:
(1) Wastewater flow, Q-50000m/d
(2) Volume of aeration tank, V-12000m
(3) Influent BOD, Y.- 300 mg/1
(4) Effluent BOD, YE - 25 mg/1
(5) Mixed liquor suspended solids (MLSS), X₁ = 2500mg/1
(6) Effluent suspended solids, Xg30mg/1
(7) Waste sludge suspended solids, X-9700mg/1
(8) Quantity of waste sludge, Q., -220m³/d
Based on the information above data, determine:
(a) Aeration period (hrs.)
(b) Food to microorganism ratio (F/M) (kg BOD per day/kg MLSS)
(c) Percentage efficiency of BOD removal
(d) Sludge age (days)
Please solve the question by hand with a detailed explanation of the steps.
Chapter 14 Solutions
EBK ENGINEERING FUNDAMENTALS: AN INTROD
Ch. 14.2 - Prob. 1BYGCh. 14.2 - Prob. 2BYGCh. 14.2 - Prob. 3BYGCh. 14.2 - Prob. 4BYGCh. 14.2 - Prob. 5BYGCh. 14.2 - Prob. BYGVCh. 14.4 - Prob. 1BYGCh. 14.4 - Prob. 2BYGCh. 14.4 - Prob. 3BYGCh. 14.4 - Prob. 4BYG
Ch. 14.4 - Prob. 5BYGCh. 14.4 - Prob. BYGVCh. 14.5 - Prob. 1BYGCh. 14.5 - Prob. 2BYGCh. 14.5 - Prob. 3BYGCh. 14.5 - Prob. 4BYGCh. 14.5 - Prob. BYGVCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Using Excel, create a table that shows the...Ch. 14 - Using Excel, create a table that shows the...Ch. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Prob. 35P
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- An average operating data for conventional activated sludge treatment plant is as follows: (1) Wastewater flow, Q = 50000m³/darrow_forwardA- Design grit removal chamber for a W.W.P with hourly flow equal 5000 m'h B-Answer five of the following: 1-....... is the storm runoff that occurs from rainfall? (15 mark) (10 mark) 2- A protective device used to remove large and coarse materials from the wastewater 3-....... utilize a relative porous bacteria growth medium such as rock or formed plastic shapes 4- There are two basic methods of introducing air into the aeration tanks are....... And ......... 5-..... to water bodies such as rivers will be described by Streeter- Phelp's equation 6- .... is the liquid conveyed by a sewer, it may consist of any one or a mixture of liquid wastes.arrow_forward(2) Volume of aeration tank, V-12000m (3) Influent BOD, Y.- 300 mg/1 (4) Effluent BOD, Y, 25 mg/1 (5) Mixed liquor suspended solids (MLSS), X,-2500mg/1 (6) Effluent suspended solids, X-30mg/1 (7) Waste sludge suspended solids, XR-9700mg/1 (8) Quantity of waste sludge, Q., 220m³/d 100 Based on the information above data, determine: (a) Aeration period (hrs.) (b) Food to microorganism ratio (F/M) (kg BOD per day/kg MLSS) (c) Percentage efficiency of BOD removal (d) Sludge age (days)arrow_forward
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- Please answer the following questions and make sure you answer each question please.arrow_forwardWater is discharged into the atmosphere through a bent nozzle of an angle (a) as shown in the figure. The cross-sectional area at the nozzle inlet and outlet are (Ain) and (Aout), respectively. The discharge through the nozzle is (Q). The gauge pressure at the nozzle inlet is (Pin). The bend lies in a horizontal plane. Ain Vin Aout X Atmosphere Vout Problem (10): Given the values of Ain [m2], Aout [m²], Pin [atm], Q [m³/s], and a [degrees], calculate the magnitude of the reaction force component in y-direction (Ry) in [N]. Givens: A in 0.169 m^2 A out Pin 0.143 m^2 0.552 atm = Q α 0.367 m^3/s = 31.72 degrees Answers: ( 1 ) 6264.193 N (2) 12041.886 N ( 3 ) 8715.747 N ( 4 ) 7139.937 Narrow_forwardProblem (12): A pump is being used to lift water from the bottom tank to the top tank in a pipe of diameter (d) at a discharge (Q). The pipe system comprises four Long radius 90° threaded elbows. The pipe entrance is sharp-edged, and the pipe exit is sudden. A Ball valve (1/3 closed) is used to control the discharge in the pipeline. Given the values of Q [Lit/s], and d [cm], calculate the power loss due to components (i.e., minor losses) in the pipe (Wminor-loss) in [W]. Givens: Q = 12.275 lit/s d = 6.266 cm Answers: ( 1 ) 1142.006 W (2) 952.086 W ( 3 ) 1225.555 W ( 4 ) 1331.216 W Loss Coefficients for Pipe Components (h,= K,Y) Component a. Elbows KL elbow Regular 90°, flanged 0.3 Regular 90°, threaded 1.5 Long radius 90°, flanged 0.2 V 90° elbow Long radius 90°, threaded 0.7 Long radius 45°, flanged 0.2 0.4 Regular 45°, threaded . 180° return bends 180° return bend, flanged 0.2 V 45° elbow 180° return bend, threaded 1.5 c. Tees Line flow, flanged 0.2 Line flow, threaded 0.9 180°…arrow_forward
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