Chapter 14, Problem 26E

Interpretation Introduction

Interpretation:

The reason for the sum of $\text{pH}$ and $\text{pOH}$ being $14.0$ at $\text{25}°\text{C}$ is to be explained.

Concept introduction:

The $\text{pH}$ of hydronium ions $\left({\text{H}}_3{\text{O}}^{+}\right)$ is calculated using the following relation:

$\text{pH}=-\log \left[{\text{H}}_3{\text{O}}^{+}\right]$

The $\text{pOH}$ of hydroxyl ions $\left({\text{OH}}^{-}\right)$ is calculated using the following relation:

$\text{pOH}=-\log \left[{\text{OH}}^{-}\right]$