Chapter 1.4, Problem 236E

For the following exercises, find the slope of a tangent line to a polar curve $r=f\left(\theta \right)$ . Let $x=r\cos \theta =f\left(\theta \right)\cos \theta$ and $y=r\sin \theta =f\left(\theta \right)\sin \theta$ , so the polar equation $r=f\left(\theta \right)$ is now written in parametric form.

236. $r=1-\sin \theta ;\left(\frac{1}{2},\frac{\pi }{6}\right)$