CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
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Chapter 14, Problem 20E
Interpretation Introduction

Interpretation:

The way given processes prevent the rusting of iron is to be explained.

Concept Introduction:

The chemical reaction in which oxidation process and reduction process take place simultaneously, is called a redox reaction.

The rusting of iron requires conduction of electrons and is an oxidation-reduction reaction.

Rusting of iron is a redox reaction that takes place in the presence of oxygen. Iron loses electrons easily and gets oxidized in the redox reaction.

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13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

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CHEMISTRY IN FOCUS W/ OWL (LL)>IP<

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