Essential Organic Chemistry (3rd Edition)
3rd Edition
ISBN: 9780321937711
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 14, Problem 19P
Interpretation Introduction
Interpretation:
Antioxidant property of catechins should be explained through resonance.
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Resonance:
Resonance is a way of describing delocalized electrons within certain molecules where the bonding cannot be expressed by one single Lewis structure.
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Students have asked these similar questions
14.46 Draw a stepwise mechanism for the following reaction.
HBr
ROOR
Br
+
Br
Show work..don't give Ai generated solution....
14.47 Addition of HCI to alkene X forms two alkyl halides Y and Z.
exocyclic C=C
X
HCI
CI
Y
+
CI Z
a. Label Y and Z as a 1,2-addition product or a 1,4-addition product.
b.Label Y and Z as the kinetic or thermodynamic product and explain
why.
c. Explain why addition of HCI occurs at the indicated C=C (called an
exocyclic double bond), rather than the other C=C (called an
endocyclic double bond).
Chapter 14 Solutions
Essential Organic Chemistry (3rd Edition)
Ch. 14.2 - Write the mechanism for the monobromination of...Ch. 14.2 - Prob. 2PCh. 14.4 - Prob. 3PCh. 14.4 - Which of the hydrogens in the structure in the...Ch. 14.4 - How many alkyl chlorides can be obtained from...Ch. 14.4 - Prob. 7PCh. 14.5 - Prob. 9PCh. 14.6 - a. Which ether is most apt to form a peroxide? b....Ch. 14.7 - Prob. 11PCh. 14 - Prob. 12P
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- 14.44 Ignoring stereoisomers, draw all products that form by addition of HBr to (E)-hexa-1,3,5-triene.arrow_forwardInclude stereochemistry Leven though the solutions manual does 14.43 Draw the products formed when each compound is treated with one not) equivalent of HBr. a. b. C.arrow_forward14.41 Label each pair of compounds as stereoisomers, conformations, or constitutional isomers: (a) A and B; (b) A and C; (c) A and D; (d) C and D. A B C Darrow_forward
- Steps and detailed explanation for work. Thanks!arrow_forward14.39 Draw the structure of each compound. a. (Z)-penta-1,3-diene in the s-trans conformation b. (2E,4Z)-1-bromo-3-methylhexa-2,4-diene c. (2E,4E,6E)-octa-2,4,6-triene d. (2E,4E)-3-methylhexa-2,4-diene in the s-cis conformationarrow_forwardPLEASE ANSWER ALL PARTS!!arrow_forward
- pls help on all, inlcude all steps.arrow_forward19. Complete the following chart for the incorrect electron configurations shown in the left column. When drawing the correct electron configuration, assume the same number of electrons that were shown in the incorrect configuration. Incorrect Electron Configuration 2p ↑↓ ↑ 2s ↑↓ 1s ↑↓↓ ਵੇ ਵੇ ਵੇ 3p ↑ ↑ ↑ - 38 ↑ 2p 2s ↑↓ 1s 2p 2s 1s ** ↑↓ ↑↓ ↑↑ 리리리 Which principle or rule is violated? Explain the violated principle or rule in your own words Draw the correct electron configurationarrow_forward14.36 Draw all reasonable resonance structures for each compound. a. + b. C. :O: d. :O: NH2 NH2 :O:arrow_forward
- 14.32 What diene and dienophile are needed to prepare each compound by a Diels-Alder reaction? a. b.arrow_forward14.34 Draw all reasonable resonance structures for each species. a. b. Ö :0: C. :0: :0: d. OH e. f. :O:arrow_forward7. The standard reduction potentials for two half-reactions are shown above. Which of the statements listed below will be true for the following reaction taking place under standard conditions? a. E° b. E° c. E° = d. E° e. E° = Al (s) + Cr³+ → Al³+ + Cr (s) 0.93 V, and the reaction is not spontaneous 0.93 V, and the reaction is spontaneous 2.39 V, and the reaction is not spontaneous 2.39 V, and the reaction is not spontaneous 0.93 V, and the reaction is spontaneous Cu2+ + 2e → Cu E° = +0.34 V Zn2+ + 2e → Zn E° = -0.76 V E° = -1.18 V Mn2+ + 2e → Mn 8. Based on the above reduction potential, which of the following reactions will occur spontaneously? a. Mn²+ + Cu → Mn + Cu2+ b. Mn²+ + Zn → Mn + Zn²+ c. Zn2+ + Cu → Zn + Cu²+ d. Zn²+ + Mn → Zn + Mn2+ e. Cu²+ + Zn²+ → Cu + Znarrow_forward
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