a. a) Graph the function. b. b) Draw tangent lines to the graph at point whose x -coordinates are –2, 0, and 1. c. c) Find f ' ( x ) by determining lim x → 0 f ( x + h ) − f ( x ) h . d. d) Find f ' ( − 2 ) , f ' ( 0 , ) and f ' ( 1 ) . These slopes should match those of the lines you drew in part ( b ). f ( x ) = 1 x
a. a) Graph the function. b. b) Draw tangent lines to the graph at point whose x -coordinates are –2, 0, and 1. c. c) Find f ' ( x ) by determining lim x → 0 f ( x + h ) − f ( x ) h . d. d) Find f ' ( − 2 ) , f ' ( 0 , ) and f ' ( 1 ) . These slopes should match those of the lines you drew in part ( b ). f ( x ) = 1 x
Solution Summary: The author illustrates the graph of the function f(x)=1x.
Find an equation for the tangent line to y = g(x) at the
point (2, g(2)). Write your result in point-slope form.
Submit
On the axes provided, sketch the tangent line to the
function g(x) at the point (2, g(2)).
-2
6
9. For each of the following functions:
a)Find an equation of the tangent line to the curve at the given point and
b) find the values of x for which the tangent line is horizontal.
i) f(x)=x* - x² at the point (1, 0)
ii) g(x) =
at the point (2, -1/2)
iii) w(x) =
1
at x=-1
1+x?
iv) s(t) = tan t t=0 and t= T
4.
%3D
Got help on the last one but I don't know what the D'L rule is.
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY