An explanation corresponding to the fact that the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13 C NMR spectrum is to be stated. Concept introduction: Depending upon the electron density or the concentration of electron around carbon, the chemical shift values of carbon varies relative to the reference signal. The terms, upfield and downfield expresses the relative location of signals. The meaning of upfield is to the right and of downfield is to the left.

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 14, Problem 14.49P

Interpretation Introduction

Interpretation: An explanation corresponding to the fact that the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13C NMR spectrum is to be stated.

Concept introduction: Depending upon the electron density or the concentration of electron around carbon, the chemical shift values of carbon varies relative to the reference signal. The terms, upfield and downfield expresses the relative location of signals. The meaning of upfield is to the right and of downfield is to the left.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 14, Problem 14.49P

Interpretation Introduction

Interpretation: An explanation corresponding to the fact that the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13C NMR spectrum is to be stated.

Concept introduction: Depending upon the electron density or the concentration of electron around carbon, the chemical shift values of carbon varies relative to the reference signal. The terms, upfield and downfield expresses the relative location of signals. The meaning of upfield is to the right and of downfield is to the left.

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Answer 3

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 14, Problem 14.49P

Interpretation Introduction

Interpretation: An explanation corresponding to the fact that the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13C NMR spectrum is to be stated.

Concept introduction: Depending upon the electron density or the concentration of electron around carbon, the chemical shift values of carbon varies relative to the reference signal. The terms, upfield and downfield expresses the relative location of signals. The meaning of upfield is to the right and of downfield is to the left.

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Check out a sample textbook solution

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Answer 4

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 14, Problem 14.49P

Interpretation Introduction