ORGANIC CHEM +SG +SAPLING >IP<
ORGANIC CHEM +SG +SAPLING >IP<
6th Edition
ISBN: 9781319171179
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 14, Problem 14.43AP
Interpretation Introduction

(a)

Interpretation:

The compound having a molecular formula C6H10 that shows IR absorptions at 3300cm1 and 2100cm1 and has peaks at δ27.3,31.0,66.7,92.8 in C13 NMR spectrum is to be identified.

Concept introduction:

The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.

Interpretation Introduction

(b)

Interpretation:

The way by which 1 hexyne and 4methyl2pentyne are distinguished by C13 NMR is to be stated.

Concept introduction:

The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)
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