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(a)
Interpretation:
The condensed electron configurations for
Concept Introduction:
The condensed electron configurations:
The arrangement or filling of electrons in the orbitals of atom in known as electron configuration. The heaver atoms contains more number of orbitals and electrons so we can’t able to write full electron configuration so this time we can writhe the nearest noble gas then followed remaining electron configuration is known as condensed electron configuration.
(a)
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Explanation of Solution
The condensed electron configurations of
(b)
Interpretation:
The magnetism of
Concept Introduction:
Magnetism:
If an element contains unpaired of electrons, it is paramagnetic.
If an element does not contains unpaired of electrons, it is diamagnetic.
(b)
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Explanation of Solution
The condensed electron configurations of
From the above electron configurations,
(c)
Interpretation:
The apparent oxidation state of
Concept Introduction:
Oxidation state:
The number of electrons lost or gain from an atom in the formation of molecule is known as oxidation number.
(c)
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Explanation of Solution
In generally
(c)
Interpretation:
The diamagnetism of
Concept Introduction:
Oxidation state:
The number of electrons lost or gain from an atom in the formation of molecule is known as oxidation number.
(c)
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Explanation of Solution
The condensed electron configurations of
From the above electron configurations,
In generally
From the above discussion,
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Chapter 14 Solutions
Loose Leaf for Chemistry: The Molecular Nature of Matter and Change
- For a titration of 40.00 mL of 0.0500 M oxalic acid H2C2O4 with 0.1000 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin;2) 15 mL; 3) 20 mL; 4) 25 mL; 5) 40 mL; 6) 50 mL. Ka1 = 5.90×10^-2, Ka2 = 6.50×10^-5 for oxalic acid.arrow_forwardPredict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forwardPredict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forward
- How many signals would you expect to find in the 1 H NMR spectrum of each given compound? Part 1 of 2 2 Part 2 of 2 HO 5 ☑ Х IIIIII***** §arrow_forwardA carbonyl compound has a molecular ion with a m/z of 86. The mass spectra of this compound also has a base peak with a m/z of 57. Draw the correct structure of this molecule. Drawingarrow_forwardCan you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forward
- Synthesize the following compound from cyclohexanol, ethanol, and any other needed reagentsarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s) Be sure to account for all bond-breaking and bond-making steps Problem 73 of 10 Drawing Amows ro HO Donearrow_forward
- 12. Synthesize the following target molecules (TMs) using the specified starting materials. .CI a) HO3S SM TM b) HO- SMarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forwardWrite the systematic name of each organic molecule: structure name show work. don't give Ai generated solutionarrow_forward
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