Concept explainers
(a)
Interpretation:
The substitutive name and common name of
Concept introduction:
The systematic naming of organic compound is given by
Rules for writing IUPAC name from the structural formula are given below.
- First, identify the longest carbon chain.
- The next step is to identify the groups attached to the longest chain.
- Identify the position, location, and a number of the substituents bonded to the carbon chain.
- Use prefix di, tri, tetra if the same type of substituents is present.
- Name the substituents in alphabetical order.

Answer to Problem 14.3P
The common name of the compound
Explanation of Solution
The compound
The compound
The number on the carbon atoms in the compound is shown below.
The compound is
The common name of the compound
(b)
Interpretation:
The substitutive name and common name of
Concept introduction:
The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.
Rules for writing IUPAC name from the structural formula are given below.
- First, identify the longest carbon chain.
- The next step is to identify the groups attached to the longest chain.
- Identify the position, location, and a number of the substituents bonded to the carbon chain.
- Use prefix di, tri, tetra if the same type of substituents is present.
- Name the substituents in alphabetical order.

Answer to Problem 14.3P
The common name of the compound
Explanation of Solution
The compound
The compound
The number on the carbon atoms in the compound is shown below.
The compound is alkyne. Therefore, -yne will be present as the suffix. The triple bond is present on the fifth carbon atom. The compound has ten-carbon atom long chain. Therefore, the substitutive name of the compound is
The common name of the compound
(c)
Interpretation:
The substitutive name of compound is to be stated.
Concept introduction:
The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.
Rules for writing IUPAC name from the structural formula are given below.
- First, identify the longest carbon chain.
- The next step is to identify the groups attached to the longest chain.
- Identify the position, location, and a number of the substituents bonded to the carbon chain.
- Use prefix di, tri, tetra if the same type of substituents is present.
- Name the substituents in alphabetical order.

Answer to Problem 14.3P
The substitutive name of the given compound is
Explanation of Solution
The structure of the given compound is shown below.
Figure 1
The compound has five carbon atom in the longest chain. Therefore, pent- will be used in the root name. The number of the carbon atoms will be started from the carbon atom which gives the lowest number to hydroxyl group in the chain.
The number on the carbon atoms in the compound is shown below.
Figure 2
The compound has methyl group and hydroxyl group. Therefore, -yne will be present as primary suffix and –ol will be present on as secondary suffix. The methyl group is resent at the second carbon. Therefore, methyl will be used as prefix. The triple bond is present on the third carbon atom and hydroxyl group is present on the second carbon atom. Therefore, the substitutive name of the compound is
The substitutive name of the given compound is
(d)
Interpretation:
The substitutive name of compound is to be stated.
Concept introduction:
The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.
Rules for writing IUPAC name from the structural formula are given below.
- First, identify the longest carbon chain.
- The next step is to identify the groups attached to the longest chain.
- Identify the position, location, and a number of the substituents bonded to the carbon chain.
- Use prefix di, tri, tetra if the same type of substituents is present.
- Name the substituents in alphabetical order.

Answer to Problem 14.3P
The substitutive name of the compound is
Explanation of Solution
The structure of the given compound is shown below.
Figure 3
The compound has seven carbon atom in the longest chain. Therefore, hept- will be used in root name. The number of the carbon atoms will be started from the carbon atom which gives lowest number to propyl group in the chain.
The number on the carbon atoms in the compound is shown below.
Figure 4
The compound has propyl group and methoxy group. Therefore, methoxy and propyl will be present as suffix. The propyl group is present at the third carbon. The triple bond is present on the first carbon atom and double bond is present at the fifth carbon atom. Therefore, the substitutive name of the compound is
The substitutive name of the given compound is
(e)
Interpretation:
The substitutive name of compound is to be stated.
Concept introduction:
The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of the organic compound is correctly interpreted from the name.
Rules for writing IUPAC name from the structural formula are given below.
- First, identify the longest carbon chain.
- The next step is to identify the groups attached to the longest chain.
- Identify the position, location, and a number of the substituents bonded to the carbon chain.
- Use prefix di, tri, tetra if the same type of substituents is present.
- Name the substituents in alphabetical order.

Answer to Problem 14.3P
The substitutive name of the given compound is
Explanation of Solution
The structure of the given compound is shown below.
Figure 5
The compound has five carbon atom in the longest chain. Therefore, pent- will be used in root name. The number of the carbon atoms will be started from the carbon atom which gives lowest number to double bond in the chain.
The number on the carbon atoms in the compound is shown below.
Figure 6
The compound has hydroxyl group. Therefore, hydroxyl will be present as prefix. The hydroxyl group is present at the third carbon. The triple bond is present on the fifth carbon atom and double bond is present at the first carbon atom. Therefore, the substitutive name of the compound is
The substitutive name of the given compound is
Want to see more full solutions like this?
Chapter 14 Solutions
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
- What is the stepwise mechanism for this reaction?arrow_forward32. Consider a two-state system in which the low energy level is 300 J mol 1 and the higher energy level is 800 J mol 1, and the temperature is 300 K. Find the population of each level. Hint: Pay attention to your units. A. What is the partition function for this system? B. What are the populations of each level? Now instead, consider a system with energy levels of 0 J mol C. Now what is the partition function? D. And what are the populations of the two levels? E. Finally, repeat the second calculation at 500 K. and 500 J mol 1 at 300 K. F. What do you notice about the populations as you increase the temperature? At what temperature would you expect the states to have equal populations?arrow_forward30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²arrow_forward
- K for each reaction step. Be sure to account for all bond-breaking and bond-making steps. HI HaC Drawing Arrows! H3C OCH3 H 4 59°F Mostly sunny H CH3 HO O CH3 'C' CH3 Select to Add Arrows CH3 1 L H&C. OCH3 H H H H Select to Add Arrows Q Search Problem 30 of 20 H. H3C + :0: H CH3 CH3 20 H2C Undo Reset Done DELLarrow_forwardDraw the principal organic product of the following reaction.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided structures, draw the curved arrows that epict the mechanistic steps for the proton transfer between a hydronium ion and a pi bond. Draw any missing organic structures in the empty boxes. Be sure to account for all lone-pairs and charges as well as bond-breaking and bond-making steps. 2 56°F Mostly cloudy F1 Drawing Arrows > Q Search F2 F3 F4 ▷11 H. H : CI: H + Undo Reset Done DELLarrow_forward
- Calculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbons. Draw out the benzene ring structure when doing itarrow_forward1) Calculate the longest and shortest wavelengths in the Lyman and Paschen series. 2) Calculate the ionization energy of He* and L2+ ions in their ground states. 3) Calculate the kinetic energy of the electron emitted upon irradiation of a H-atom in ground state by a 50-nm radiation.arrow_forwardCalculate the ionization energy of He+ and Li²+ ions in their ground states. Thannnxxxxx sirrr Ahehehehehejh27278283-4;*; shebehebbw $+$;$-;$-28283773838 hahhehdvaarrow_forward
- Plleeaasseee solllveeee question 3 andd thankss sirr, don't solve it by AI plleeaasseee don't use AIarrow_forwardCalculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbonsarrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





