Chapter 14, Problem 14.29P

Nitric oxide (NO) emissions from automobile exhaust can be reduced by using a catalytic converter, and the following reaction occurs at the catalytic surface:
$\text{NO}+\text{CO}\to \frac{1}{2}{\text{N}}_2+{\text{CO}}_2$
The concentration of NO is reduced by passing the exhaust gases over the surface, and the rate of reduction at the catalyst is governed by a first-order reaction of the form given by Equation 14.66. As a first approximation it may be assumed that NO reaches the surface by one-dimensional diffusion through a thin gas film of thickness L that adjoins the surface. Referring to Figure 14.7, consider a situation for which the exhaust gas is at 500°C and 1.2 bars and the mole fraction of NO is $x_{A,L}=0.15$ . If $D_{AB}={10}^{-4}$ m²/s, $k_1^{"}=0.05$ $m/s$ , and the film thickness is L = 1 mm, what k the mole fraction of NO at the catalytic surf ace and what is the NO removal rate for a surface of area $A=200c{m}^2$ ?