PRACT STAT W/ ACCESS 6MO LOOSELEAF
PRACT STAT W/ ACCESS 6MO LOOSELEAF
4th Edition
ISBN: 9781319215361
Author: BALDI
Publisher: Macmillan Higher Education
Question
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Chapter 14, Problem 14.1AYK

a)

To determine

To find: The standard deviation of the sampling distribution.

a)

Expert Solution
Check Mark

Answer to Problem 14.1AYK

The standard deviation is 0.40.

Explanation of Solution

Given:

Population mean (µ)

Standard deviation (s) = 8

Sample size ( n ) = 400

Calculation:

The standard deviation of the sampling distribution is calculated as:

  σ=σn=8400=0.40

Thus, the standard deviation is 0.40.

b)

To determine

To construct: A normal curve that explains the variability of PRACT STAT W/ ACCESS 6MO LOOSELEAF, Chapter 14, Problem 14.1AYK , additional homework tip  1 in many samples for the -provided population. Also, find the missing number using the 68-99-99.7 rule

b)

Expert Solution
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Explanation of Solution

Graph:

The figure could be constructed as:  PRACT STAT W/ ACCESS 6MO LOOSELEAF, Chapter 14, Problem 14.1AYK , additional homework tip  2

Calculation:

The margin of error could be constructed as:

  2×σ=2×0.4=0.82×σ=2×0.4=0.8

The values of x¯ will range from -0.8 to 0.8.

Using these values, the figure is:

  PRACT STAT W/ ACCESS 6MO LOOSELEAF, Chapter 14, Problem 14.1AYK , additional homework tip  3

c)

To determine

To construct: The interval below the sketch for one of x¯ that is lying the shaded region and other lying outside the shaded region.

c)

Expert Solution
Check Mark

Explanation of Solution

Graph:

The figure could be constructed as:

  PRACT STAT W/ ACCESS 6MO LOOSELEAF, Chapter 14, Problem 14.1AYK , additional homework tip  4

d)

To determine

To find: The percent of all samples would the confidence interval x¯±m contain the true population mean μ=140

d)

Expert Solution
Check Mark

Answer to Problem 14.1AYK

The percentage is 95%.

Explanation of Solution

Calculation:

The percent of all the samples that would fall in the computed confidence interval is 95%. In this case, m is 0.8 and μ=140 about 95% of all the samples would be in the confidence interval.

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