Solution Manual for Quantitative Chemical Analysis
Solution Manual for Quantitative Chemical Analysis
9th Edition
ISBN: 9781464175633
Author: Daniel Harris
Publisher: Palgrave Macmillan Higher Ed
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Chapter 14, Problem 14.17P

a)

Interpretation Introduction

Interpretation:

The line notation for the given cell has to be written.

Concept Introduction:

Line notation:

Electrochemical cells are explained with the help of notation expressed with two symbols: |phaseboundarysaltbridge

Each phase boundary is represented by a vertical line and the electrodes are seen at the extreme right and left hands of the line diagram.

An example of line notation is Cd(s)|Cd(NO3)2(aq)AgNO(3)(aq)|Ag(s)

b)

Interpretation Introduction

Interpretation:

The potential of each half cell, the cell voltage and direction of flow of electrons and spontaneous net cell reaction has to be written.

c)

Interpretation Introduction

Interpretation:

The limiting reagent has to be identified.

d)

Interpretation Introduction

Interpretation:

The amount of electrical work to be done when 0.231 ml Br2 will be consumed has to be calculated.

e)

Interpretation Introduction

Interpretation:

The rate (in grams per second) of dissolution of Al(s) has to be given.

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Draw the anti-Markovnikov product of the hydration of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for esc esc ☐ Explanation Check F1 1 2 F2 # 3 F3 + $ 14 × 1. BH THE BH3 2. H O NaOH '2 2' Click and drag to start drawing a structure. F4 Q W E R A S D % 905 LL F5 F6 F7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility < & 6 7 27 8 T Y U G H I F8 F9 F10 F11 F12 9 0 J K L P + // command option Z X C V B N M H H rol option command
AG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, N

Chapter 14 Solutions

Solution Manual for Quantitative Chemical Analysis

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