Chapter 14, Problem 14.16P

Interpretation Introduction

Interpretation:

For given half-reaction Nernst equation has to be written and value of E when $\text{pH}$ is 3.00 and ${\text{P}}_{{\text{AsH}}_{\text{3}}}\text{=1}\text{.0 bar}$ has to be calculated.

Concept introduction:

Nernst equation is,

${\text{E = E}}_{\text{o}}\text{-}\frac{0.05916}{\text{n}}\text{ln}\text{Q}$

Where,

$\begin{array}{l}{\text{E}}_{\text{o}}\text{-Standardpotentialofthecell}\\ \\ \text{n - Number of electrons}\\ \\ \text{Q - Reactant quotient}\end{array}$