A mixture of 0.0565 mol phosphorus pentachloride, PCl 5 , and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl 3 , and chlorine gas, Cl 2 . The helium gas is inert. PCl 5 ( g ) ⇌ PCl 3 ( g ) + Cl 2 ( g ) What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is K c for the dissociation of PCl 5 ?
A mixture of 0.0565 mol phosphorus pentachloride, PCl 5 , and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl 3 , and chlorine gas, Cl 2 . The helium gas is inert. PCl 5 ( g ) ⇌ PCl 3 ( g ) + Cl 2 ( g ) What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is K c for the dissociation of PCl 5 ?
Solution Summary: The author explains the equilibrium constant, which is the ratio of the rate constants of forward and reverse reactions at a given temperature.
A mixture of 0.0565 mol phosphorus pentachloride, PCl5, and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0°C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl3, and chlorine gas, Cl2. The helium gas is inert.
PCl
5
(
g
)
⇌
PCl
3
(
g
)
+
Cl
2
(
g
)
What is the partial pressure of helium in this equilibrium mixture at 250.0°C? At equilibrium, the total pressure is found to be 6.505 atm. What is Kc for the dissociation of PCl5?
Please correct answer and don't used hand raiting and don't used Ai solution
Please correct answer and don't used hand raiting
Consider the following Figure 2 and two atoms that are initially an infinite distance apart, x =00, at which point
the potential energy of the system is U = 0. If they are brought together to x = x, the potential energy is related
to the total force P by
dU
dx
= P
Given this, qualitatively sketch the variation of U with x. What happens at x=x? What is the significance of
x = x, in terms of the potential energy?
0
P, Force
19
Attraction
Total
Repulsion
x, Distance
Figure 2. Variation with distance of the attractive, repulsive, and total forces between atoms. The
slope dP/dx at the equilibrium spacing xe is proportional to the elastic modulus E; the stress σb,
corresponding to the peak in total force, is the theoretical cohesive strength.
Chapter 14 Solutions
Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th
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