Chapter 14, Problem 14.125CP

Interpretation Introduction

Interpretation:

Heavy water, symbolized $D_{2}O(D{=}^{2}H)$finds use as a neutron moderation in nuclear reactions in a mixture with ordinary water exchange occurs according equations

Concept introduction:

Heavy water is containing a higher −than normal proportion of $H_{2}O$as elaterium podium oxide $HDO$

Given:

1.00 mol of $H_{2}O$ is combined with 1.00 mol of $D_{2}O$ equilibrium amounts $H_{2}O$ , $D_{2}O$ and $HDO$

$H_{2}O+D_{2}O\rightleftharpoons 2HDO{K}_C=3.86at298K$