Chemistry For Changing Times (14th Edition)
14th Edition
ISBN: 9780321972026
Author: John W. Hill, Terry W. McCreary
Publisher: PEARSON
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Chapter 14, Problem 12P
Interpretation Introduction
Interpretation:
Using the concept of hyperdense hydrogen bonding in explaining the reason for the density of ice being less than that of liquid water.
Concept Introduction:
Hyperdense hydrogen bonding is the electrostatic hyper attraction force between positive charged and negative charged hydrogen having a lone pair of electrons.
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Using wedge-and-dash bonds, modify the bonds on the chiral carbon in the molecule below so the molecule has R stereochemical configuration.
NH
H
Br
X
टे
Provide photos of models of the following molecules. (Include a key for identification of the atoms)
1,2-dichloropropane
2,3,3-trimethylhexane
2-bromo-3-methybutane
Please draw the structure in the box that is consistent with all the spectral data and
alphabetically label all of the equivalent protons in the structure (Ha, Hb, Hc....) in order to assign all
the proton NMR peaks. The integrations are computer generated and approximate the number of
equivalent protons. Molecular formula: C13H1802
14
13
12
11
10
11 (ppm)
Structure with assigned H peaks
2.08
3.13
Chapter 14 Solutions
Chemistry For Changing Times (14th Edition)
Ch. 14 - Prob. 1RQCh. 14 - Why should foods be frozen swiftly rather than...Ch. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQ
Ch. 14 - Prob. 11RQCh. 14 - Prob. 12PCh. 14 - What consequences does the lower density of ice...Ch. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Prob. 35PCh. 14 - Prob. 36PCh. 14 - Prob. 37PCh. 14 - Prob. 38PCh. 14 - Prob. 39PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Prob. 42PCh. 14 - Prob. 43PCh. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Prob. 46PCh. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Prob. 49PCh. 14 - Prob. 50PCh. 14 - Prob. 51PCh. 14 - Prob. 52PCh. 14 - Prob. 53PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - Prob. 56PCh. 14 - Prob. 57APCh. 14 - Prob. 58APCh. 14 - Prob. 59APCh. 14 - Prob. 60APCh. 14 - Prob. 61APCh. 14 - Prob. 62APCh. 14 - Prob. 63APCh. 14 - Prob. 64APCh. 14 - Prob. 65APCh. 14 - Prob. 66APCh. 14 - Prob. 67APCh. 14 - Prob. 68APCh. 14 - Prob. 69APCh. 14 - Prob. 70APCh. 14 - Prob. 71APCh. 14 - Prob. 14.1CTECh. 14 - Prob. 14.2CTECh. 14 - Prob. 14.3CTECh. 14 - Prob. 14.4CTECh. 14 - Prob. 14.5CTECh. 14 - Prob. 14.6CTECh. 14 - Prob. 14.7CTECh. 14 - Prob. 1CGPCh. 14 - Prob. 2CGPCh. 14 - Prob. 3CGPCh. 14 - Prob. 4CGPCh. 14 - Prob. 5CGPCh. 14 - Prob. 6CGPCh. 14 - Prob. 7CGPCh. 14 - Prob. 8CGPCh. 14 - Prob. 9CGPCh. 14 - Prob. 1CHQCh. 14 - Prob. 2CHQCh. 14 - Prob. 3CHQCh. 14 - Prob. 4CHQ
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