Chapter 14, Problem 127E

Interpretation Introduction

Interpretation: The $\text{pH}$ of the given $0.050\text{M}$ solution of $\text{Al}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}$ is to be calculated.

Concept introduction: The $\text{pH}$ of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The $\text{pH}$ of a solution is calculated by the formula, $\text{pH}=-\log \left[{\text{H}}^{+}\right]$

The sum, $\text{pH}+\text{pOH}=14$

The equilibrium constant for water is denoted by $K_{\text{w}}$ and is expressed as,

$K_{\text{w}}=\left[{\text{H}}^{+}\right]\left[{\text{OH}}^{-}\right]$

The value of $K_{\text{w}}$ is calculated by the formula,

$K_{\text{w}}=K_{\text{a}}\cdot K_{\text{b}}$