(a) Explanation Express the complete combustion reaction with theoretical air. [ ( 6.64 C + 2.85 H 2 + 0.31 O 2 + 0.05 N 2 + 0.02 S ) + α th ( O 2 + 3.76 N 2 ) ] → ( b CO 2 + c H 2 O + d SO 2 + e N 2 ) (I) Here, stoichiometric coefficient of air is a th , hydrogen is H 2 , oxygen is O 2 , nitrogen is N 2 , sulfur dioxide is SO 2 , carbon dioxide is CO 2 , water is H 2 O and number of moles of oxygen, carbon dioxide, sulfur dioxide, water and nitrogen is b , c , d and e respectively. Express the air–fuel ratio on a mass basis. A F = a th N air M air m C + m H 2 + m O 2 + m N 2 + m S + m Ash (II) Here, number of moles of air is N air and molar mass of air is M air . Conclusion: Refer Table A-1, “atomic or molecular weights”, and write the molar masses of given species. M C = 12.01 kg / kmol M H 2 = 2.016 kg / kmol M O 2 = 32 .00 kg / kmol M N 2 = 28 .01 kg / kmol M S = 32 .06 kg / kmol Here, molar mass of carbon, hydrogen, oxygen, nitrogen and sulfur is M C , M H , M O 2 , M N 2 and M S respectively. Represent the amounts of the substances on the basis of 100 kg of coal as in Table (I). Substance m i ( kg ) M ( kg / kmol ) N i = m i M i ( kmol ) Carbon ( C ) 79.2 12.01 6.60 Hydrogen ( H 2 ) 5 (b) To determine The amount of SO 2 produced, in kg per kg of coal.

Fundamentals of Engineering Thermodynamics, Binder Ready Version

8th Edition

ISBN: 9781118820445

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 13.8, Problem 13P

(a)

To determine

The air–fuel ratio on a mass basis.

(b)

To determine

The amount of SO2 produced, in kg per kg of coal.

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Chapter 13.8, Problem 12P

Chapter 13.8, Problem 14P

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Chapter 13 Solutions

Fundamentals of Engineering Thermodynamics, Binder Ready Version

Ch. 13.8 - Prob. 1E Ch. 13.8 - Prob. 2E Ch. 13.8 - Prob. 3E Ch. 13.8 - Prob. 4E Ch. 13.8 - Prob. 5E Ch. 13.8 - Prob. 6E Ch. 13.8 - Prob. 7E Ch. 13.8 - Prob. 8E Ch. 13.8 - Prob. 9E Ch. 13.8 - Prob. 10E

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