Tangent Planes Let f be a differentiable function and consider the surface z = x f ( y x ) Show that the tangent plane at any point P ( x 0 , y 0 , z 0 ) on the surface passes through the origin.
Tangent Planes Let f be a differentiable function and consider the surface z = x f ( y x ) Show that the tangent plane at any point P ( x 0 , y 0 , z 0 ) on the surface passes through the origin.
Solution Summary: The author explains that the tangent plane passes through the origin. The equation of the surface is given by z=xfleft.
Tangent Planes Let f be a differentiable function and consider the surface
z
=
x
f
(
y
x
)
Show that the tangent plane at any point
P
(
x
0
,
y
0
,
z
0
)
on the surface passes through the origin.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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