Explanation Given information: It is provided that curl E → = − ∂ B → ∂ t and curl H → = σ E → + ε ∂ E → ∂ t ; where E → is electric intensity, B → is magnetic flux density, H → is magnetic intensity, and σ , ε , and μ are positive constants. Consider the linearly polarized plane wave travelling in the x − direction at the speed of light c . E → ( x , t ) = E ( x , t ) j ^ and B → ( x , t ) = B ( x , t ) k ^ . It is given that the charge density Q is 0 so that div E → = 0 . Now, curl E → = | i j k ∂ ∂ x ∂ ∂ y ∂ ∂ z 0 E → ( x , t ) 0 | = ∂ E ∂ x k ^ We know that, curl E → = − ∂ B → ∂ t So, ∂ E ∂ x = − ∂ B → ∂ t

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 13.7, Problem 60PS

To determine

To derive: Maxwell’s electric intensity equation, (∇⋅∇)E→=μσ∂E→∂t+με∂2E→∂t2 , assuming that the charge density Q is 0 so that divE→=0 .

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Chapter 13.7, Problem 59PS

Chapter 13, Problem 1PE

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Chapter 13 Solutions

Calculus

Ch. 13.1 - Prob. 1PS Ch. 13.1 - Prob. 2PS Ch. 13.1 - Prob. 3PS Ch. 13.1 - Prob. 4PS Ch. 13.1 - Prob. 5PS Ch. 13.1 - Prob. 6PS Ch. 13.1 - Prob. 7PS Ch. 13.1 - Prob. 8PS Ch. 13.1 - Prob. 9PS Ch. 13.1 - Prob. 10PS

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To derive: Maxwell’s electric intensity equation, ( ∇ ⋅ ∇ ) E → = μ σ ∂ E → ∂ t + μ ε ∂ 2 E → ∂ t 2 , assuming that the charge density Q is 0 so that div E → = 0 .

Solution Summary: The author explains Maxwell's electric intensity equation, assuming that the charge density Q is 0 so that divstackrelto

To derive: Maxwell’s electric intensity equation, (∇⋅∇)E→=μσ∂E→∂t+με∂2E→∂t2 , assuming that the charge density Q is 0 so that divE→=0 .

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Chapter 13 Solutions