Instantaneous Velocity of a Ball In physics it is shown that the height s of a ball thrown straight down with an initial velocity of 48 ft/sec from rooftop 160 feet high is, s = s ( t ) = − 16 t 2 − 48 t + 160 where t is the elapsed time that the ball is in the air. a. When does the ball strike the ground? That is, how long is the ball in the air?

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Answer 1

Question

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

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Answer 2

Question

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Answer 6

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

Answer 7

Chapter 13.4, Problem 48AYU

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

a. When does the ball strike the ground? That is, how long is the ball in the air?

Answer 8

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

Answer 9

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

b. What is the average velocity of the ball from $t = 0 to t = 1$ ?

Answer 10

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

Answer 11

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

c. What is the instantaneous velocity of the ball at time $t$ ?

Answer 12

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

Answer 13

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

d. What is the instantaneous velocity of the ball at $t = 1$ ?

Answer 14

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Answer 15

To determine

To find: Instantaneous Velocity of a Ball In physics it is shown that the height $s$ of a ball thrown straight down with an initial velocity of $48 ft/sec$ from rooftop 160 feet high is,

$s = s (t) = - 16 t^{2} - 48 t + 160$

where $t$ is the elapsed time that the ball is in the air.

e. What is the instantaneous velocity of the ball when it strikes the ground?

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Check out a sample textbook solution

See solution

Answer 19

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