The volume V of a right circular cone of radius r and height h is given by V = 1 3 π r 2 h . Suppose that the height decreases from 50 cm to 49.64 cm and the radius increases from 10 cm to 10.15 cm . Compare the change in volume of the cone with an approximation of this change using a total differential.
The volume V of a right circular cone of radius r and height h is given by V = 1 3 π r 2 h . Suppose that the height decreases from 50 cm to 49.64 cm and the radius increases from 10 cm to 10.15 cm . Compare the change in volume of the cone with an approximation of this change using a total differential.
Solution Summary: The author compares the change in volume V of a right circular cone with its radius and height.
The volume
V
of a right circular cone of radius
r
and height
h
is given by
V
=
1
3
π
r
2
h
. Suppose that the height decreases from
50
cm
to
49.64
cm
and the radius increases from
10
cm
to
10.15
cm
. Compare the change in volume of the cone with an approximation of this change using a total differential.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
For each given function f(x) find f'(x) using the rules learned in section 9.5.
1. f(x)=x32
32x
2. f(x)=7x+13
3. f(x) =
x4
4. f(x) = √√x³
5. f(x) = 3x²+
3
x2
Find:
lim x →-6 f (x)
limx-4 f (x)
lim x-1 f (x)
lim x →4 f (x)
(-6,3) •
(-1,5)
-8
-7
(-6,-2)
4+
(4,5)
(4,2) •
(-1,1)
-6
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Fundamental Theorem of Calculus 1 | Geometric Idea + Chain Rule Example; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=hAfpl8jLFOs;License: Standard YouTube License, CC-BY