Explanation Calculation: Consider the limit. lim x , y → 0 , 0 ln 1 + x 2 y 3 The continuity properties states that: 1: For two continuous functions, their composition is continuous. 2: For two continuous functions, their sum, difference or product is continuous. 3: For two continuous functions, their quotient is continuous, except where the denominator is zero. The limit of a sum is the sum of the limits and the limit of a product is the product of the limits. lim x , y → 0 , 0 ln 1 + x 2 y 3 = ln lim x , y → 0 , 0 1 + x 2</

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Author: Anton, Howard, Bivens, Irl C., Davis, Stephen

Publisher: WILEY

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Chapter 13.2, Problem 5ES

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To calculate: The value of the limit, limx,y→0,0ln1+x2y3 , by using the limit laws and continuity properties.

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Chapter 13.2, Problem 4ES

Chapter 13.2, Problem 6ES

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The value of the limit, lim x , y → 0 , 0 ln 1 + x 2 y 3 , by using the limit laws and continuity properties.

Solution Summary: The author calculates the value of the limit by using limit laws and continuity properties.

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To calculate: The value of the limit, limx,y→0,0ln1+x2y3 , by using the limit laws and continuity properties.

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Chapter 13 Solutions