Chapter 13.4, Problem 18E

To determine

To find the probability that $4$ is shown on green number cube and $5$ is shown on red number cube.

Answer to Problem 18E

Independent, $\frac{1}{36}$

Explanation of Solution

Given:

A bowl of $5$ oranges and $4$ tangerines.

Calculation:

The events are independent because outcome of one eventdoesn’t affect the outcome of another event.

Let A be the event of showing $4$ on green number cube

Let B be the event of showing $5$ on red number cube.

Total sample space $=6$

Therefore probability of event A is $P(A)=\frac{1}{6}$

Therefore probability of event B is $P(B)=\frac{1}{6}$

Hence,

  $\begin{array}{l}P(A\text{ and }B)=P(A)\times P(B)\\ P(A\text{ and }B)=\frac{1}{6}\times \frac{1}{6}=\frac{1}{36}\end{array}$