Explanation Given Mass of maple syrup (solvent) is 100.0 0 g . Mass of calcium (solute) in syrup is 67 mg . Density of the maple syrup is 1 .325 g/mL . The conversion of milligram ( mg ) into gram ( g ) is done as, 1 mg = 10 − 3 g Hence, the conversion of 67 mg into gram ( g ) is, 67 mg = 10 − 3 g 1 mg × 67 mg = 0.067 g Number of moles of calcium present in syrup solution is calculated by the formula, Moles of calcium = Mass of calcium atomic mass of calcium Substitute the value of mass of calcium and atomic mass of calcium ( 40.078 g/mol ) in the above equation. Moles of calcium = 0.067 g 40.078 g/mol = 1.67 × 10 − 3 mol Mass of solution is calculated as, Mass of solution = Mass of solute + Mass of solvent Substitute the value of mass of solute and mass of solvent in above equation. Mass of solution = 0.067 g + 100

14th Edition

ISBN: 9781323654378

Author: Brown

Publisher: PEARSON

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Chapter 13.4, Problem 13.6.1PE

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To determine: The molarity of calcium in maple syrup.

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Chapter 13.4, Problem 13.5.2PE

Chapter 13.4, Problem 13.6.2PE

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Chapter 13 Solutions

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